What's 2*80 in Hexa?

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The result is shown to be 1B. How did we get this value?


So, this looks like a case of carry in hexa addition, so how'd we do this calculation?




I'm asking this question because of this. Here' for j=8, Round Constant is 80. The formula to find next round constant is to multiply the current round constant with 2. So, it's 2*80 and should be 100. But it's not the case. So, I want to know how is it done?

 

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They look like powers of 2.
power of 2 = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
value in decimal = 1, 2, 4, 8,16,32,64,128,256,512
value in hex = 1, 2, 4, 8,10,20,40, 80,100,200

hex 80 in decimal = 8x16 + 0x1 = 8x16 = 128
decimal 128x2 = 256
256 in hex = 256/16 power 2, therfore 1 in third column = 100

No idea why table is like that, it indeed looks wrong.

1B = 16 + 11 = 27
36 = 3x16+6 = 54

Seems they are wrong to me, these values in no way are r[j-1]*2

 

that's a special case. if the previous RC is greater than 80, they add 11B or sth.