Shell Programming Help Please

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Hi

Im working on a shell programming project at uni and wanted to ask you guys something..

Code:

wc -l SampleFile

Is the command im running and assume I have 42 lines in SampleFile, output would be:

Code:

42 SampleFile

How do remove the "SampleFile" and just end up with 42?

Thanks for the help!

 

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Pipe the output of wc into sed and use a regular expression to select and delete the a-z and A-Z characters.

 

Code:

sed | wc -l SampleFile /[A..Z,a..z]

I cant try it out at the moment.. but something like that? :rolleyes

btw how you doing buddy? long time.....

 

If you're doing it in a script use a variable that will equal the file name, but manually you can do it like this: wc -l SampleFile | sed -e 's/SampleFile//'

Here's how you would do it from a script using a variable so it can be automated to use with any file name:
a='SampleFile'
wc -l $a | sed -e 's/'"$a"'//'

Just remember your script has to have a way to read the file name into the variable.

 

Cheers freddy!! gonna use the manual one

 

I figured awk would do the same so I played around with it. Here's another solution.

wc -l filename | awk '{print $1}'

 

Another way of doing this is:
set `wc -l filename` ; echo $1

Harry.

 

And the simplest one of all (I think):

cat filename | wc -l

Harry.

 

Thanks for all the help guys!