70-215 QOTD 10/06/2004

Discussion in 'Windows Server 2003 / 2008 / 2012 / 2016' started by AJ, Jun 10, 2004.

  1. AJ

    AJ 01000001 01100100 01101101 01101001 01101110 Administrator

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    The ring topology within a Windows 2000 site is generated by which of the following technologies or components?

    A) KCC

    B) FRS

    C) Dfs

    D) Kerberos

    E) KET
     
    Certifications: MCSE, MCSA (messaging), ITIL Foundation v3
    WIP: Breathing in and out, but not out and in, that's just wrong
  2. Phil
    Honorary Member

    Phil Gigabyte Poster

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    A the KCC.
     
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  3. tripwire45
    Honorary Member

    tripwire45 Zettabyte Poster

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    I'm going with Phil. Give me an A.
     
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  4. nugget
    Honorary Member

    nugget Junior toady

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    I'll take an A too.
     
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  5. tripwire45
    Honorary Member

    tripwire45 Zettabyte Poster

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    AJ, the official answer is......?
     
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  6. Phoenix
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    Phoenix 53656e696f7220 4d6f64

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    A for me too
    forgot about these ones lol
     
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  7. AJ

    AJ 01000001 01100100 01101101 01101001 01101110 Administrator

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    Sorry about the delay folks but I've been away for a couple of days :D

    Correct answer is: A

    Explanation: Within a site, a process called the Knowledge Consistency Checker (KCC) generates a ring topology for replication among domain controllers in the same domain. The generated topology defines paths for directory updates to flow from one domain controller to another until all domain controllers have received the directory updates.
    This ring structure guarantees that there are at least two replication paths from one domain controller to another, ensuring that if one domain controller is temporarily down, replication will continue to all other domain controllers. In addition, the ring structure is created such that an update takes, at most, three "hops" from the domain controller where it originates to any other domain controller in the site.
     
    Certifications: MCSE, MCSA (messaging), ITIL Foundation v3
    WIP: Breathing in and out, but not out and in, that's just wrong

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