70-215 QOTD 05/07/2004

Discussion in 'Windows Server 2003 / 2008 / 2012 / 2016' started by AJ, Jul 5, 2004.

  1. AJ

    AJ 01000001 01100100 01101101 01101001 01101110 Administrator

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    You are building a Windows 2000 Advanced Server as the network file server for users. The system has 5 SCSI hard disks and converted to dynamic disk. The five hard disks are configured as follow:

    -- Hard disk 0: 30 GB, System and Boot volume.
    -- Hard disk 1: 20 GB, unused.
    -- Hard disk 2: 30 GB, unused.
    -- Hard disk 3: 40 GB, unused.
    -- Hard disk 4: 50 GB, unused. You decide to create a RAID-5 volume that includes all unused hard disks using Windows 2000 Disk Management. What is the largest size of the RAID-5 volume?

    A) 60 GB.

    B) 80 GB.

    C) 100 GB.

    D) 120 GB.

    E) 140 GB.
     
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  2. Jakamoko
    Honorary Member

    Jakamoko On the move again ...

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    Answer A: Largest volume size can be 20Gb (all must be same size). Can't use System volume, so 4 drives available, minus 1 volume for parity:

    4x20Gb - 20Gb = 60 Gb
     
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  3. flex22

    flex22 Gigabyte Poster

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    A............................ is what it is[​IMG]
     
  4. AJ

    AJ 01000001 01100100 01101101 01101001 01101110 Administrator

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    Correct answer is: A

    Explanation:

    The equation to determine the amount of space used in the RAID 5 volume is the total number of space in the RAID 5 volume less one volume. The more disks that you have in the RAID-5 volume, the less the cost of the redundant data stripe.

    In this question, there are 4 unused hard disks. The maximum size of each slot of the RAID-5 will be based on the smallest hard disk, which is 20 GB.

    Available disk space = (4 * 20 GB) - 20 GB = 60 GB

    HOW TO: Establish a Striped Volume with Parity (RAID-5) in Windows 2000
     
    Certifications: MCSE, MCSA (messaging), ITIL Foundation v3
    WIP: Breathing in and out, but not out and in, that's just wrong
  5. Jakamoko
    Honorary Member

    Jakamoko On the move again ...

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    ....or what I said 8)
     
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