Subnetting Question

Discussion in 'Network+' started by Jaron78, Jul 23, 2016.

  1. Jaron78

    Jaron78 Gigabyte Poster

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    upload_2016-7-23_10-35-13.png


    11000000.10100100.00110010.10011011 (192.168.50.155)
    11111111 11111111 11110000 00000000 (255.255.240.0)
    11000000 10100100 00110000 00000000 (192.168.48.0)

    Question(s) being:

    Is my calculations correct?
    How is Answer C the correct answer?

    Thanks
     
  2. SLTed

    SLTed New Member

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    Yes. Your calculations are correct. You have presented the network address of the subnet. The broadcast address is the last IP address of the network, not the IP address before the network address.
    If you want your answer to be correct the question would have the network address 192.168.32.0/20
     
  3. SLTed

    SLTed New Member

    2
    0
    1
    Yes. Your calculations are correct. You have presented the network address of the subnet. The broadcast address is the last IP address of the network, not the IP address before the network address.
    If you want your answer to be correct the question would have the network address 192.168.32.0/20
     

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