Subnetting -Working out the total available number of Networks and Subnets

"joji computerpower" · May 20, 2009

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Tinus1959 said: ↑

Ok, You say you have a subnetmask of 255.255.248.0. But that is not all you need to know. You also need to have the address of your network. Let me explain. Say your networkaddress is 64.17.43.15. 64 tells you you are working in an A-class network. An A-class network has a standard SNM of 255.0.0.0, in other words, there are 8 bits allready counted for. 255.255.248.0 has 21 bits, so 21 - 8 = 13 bits to play with. 13 bits give you a total amount of 2^13 = roughly 8000 networks. The 11 zeros on your SNM give you 2^11 = 2048 addresses. You need to lose 2, one for the network address and one for the broadcast address, leaving 2046.

If the starting address was however 130.16.25.10, that would give you a B-class to start with, so 16 bits are allready acounted for. leaving 5 bits for your networks (that's 32 networks). The number of hosts stays the same.
Click to expand...

Hi there sorry i just happend to be on the same subject. This information at first was confusing with the 11 but now i have a fair idea. Thank you very much for posting.

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