Quiz

Discussion in 'The Lounge - Off Topic' started by shambles, Jun 28, 2007.

  1. shambles

    shambles Guest

    Let's start with an easy one:

    687474703a2f2f7777772e626f6f686261682e636f6d2f7a6f6e652e68746d6c

    ignore the space seperating the last four characters from the rest of it - it shouldn't be there, but I can't get rid of it for some reason...
     
  2. noelg24

    noelg24 Terabyte Poster

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    ok what did I miss? :blink:
     
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  3. hbroomhall

    hbroomhall Petabyte Poster Gold Member

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    Code:
    http://www.boohbah.com/zone.html
    Harry.
     
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  4. noelg24

    noelg24 Terabyte Poster

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    :blink :unsure
     
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  5. shambles

    shambles Guest

    Too easy?

    How about this?

    2149463071

    There's some stuff missing, but it works fine without them...
     
  6. Headache

    Headache Gigabyte Poster

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    *head scratch*
     
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  7. Tinus1959

    Tinus1959 Gigabyte Poster

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    This would be: 128.30.52.31
    The first one is the same number, but in decimal. For the computer is doesn't make any difference if you enter the address as decimal, string, dotted decimal, hexadecimal or binairy.
    You only have to tell it that it is hex code.
     
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  8. shambles

    shambles Guest

    You Guys are too good...

    What about a change from Maths..? Still with a computing theme...

    Without using the Internet (that would be cheating...), who is missing from this lineup?

    Inky, Binky, Pinky...

    I reckon no-one knows this without having to look it up...
     
  9. Tinus1959

    Tinus1959 Gigabyte Poster

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    I think it is a childrens ryhme. Poo?
     
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  10. Tinus1959

    Tinus1959 Gigabyte Poster

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    But I like math (or logic) better. Try this:

    You have 12 coins. 11 are ok, 1 is false. It is of a different weight, but you do NOT know if it is lighter or heavier.
    You have a balanced set of scales, and you are allowed just 3 tries to tell me which coin is false, and if it is lighter or heavier.

    good luck.
     
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  11. shambles

    shambles Guest

    Whilst I'm thinking around your coins, Here's another IT-related numbers problem...

    What is the next number in this sequence..?

    1,1,10,11,101,1000,1101,10101,100010...

    :)
     
  12. zebulebu

    zebulebu Terabyte Poster

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    Too easy

    110111
     
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  13. Tinus1959

    Tinus1959 Gigabyte Poster

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    Easy:biggrin
    1,1,2,3,5,8,13,21,34,55
    So that would be 110111

    BTW, that is not IT related.:p
     
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  14. zebulebu

    zebulebu Terabyte Poster

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    QFT - until boffins find a way of introducing Fibonacci numbers into processor design...
     
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  15. zebulebu

    zebulebu Terabyte Poster

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    LOL - as if

    I spent my formative years chasing 'em around that poxy maze...
    Right turn:
    [​IMG]
    CLYDE!!
     
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  16. BosonMichael
    Honorary Member Highly Decorated Member Award 500 Likes Award

    BosonMichael Yottabyte Poster

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    If you mean the second one is "Blinky", not "Binky", then the last one is either Clyde or Sue, depending on whether you're playing the original or the feminine sequel.
     
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  17. Dhughes

    Dhughes Byte Poster

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    :eek: :eek: :eek: :cry: :cry: :eek: :eek: :eek:


    would it take months to explain this to me?



    I have a question , a question which they say their is no answer, but theiir is and its obvious lol


    If a tree falls in the forest and nobody is around to hear it does it make a sound?
     
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  18. Sparky
    Highly Decorated Member Award 500 Likes Award

    Sparky Zettabyte Poster Moderator

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    Yes, it makes a sound :biggrin
     
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  19. Tinus1959

    Tinus1959 Gigabyte Poster

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    Pacman!
     
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  20. shambles

    shambles Guest

    Ok - Fibonnaci is not IT related. Binary numbers are, though...

    Yes, typing error - missing an 'l' in Blinky. Sorry. I don't suppose (again, without looking it up), for a bonus zillion points, anyone knows their original japanese names?

    Regarding the coin puzzle - I have some of it, I think. Without giving too much away and spoiling the fun, I think the first measurement is of 8 coins, (4 on each side) and the second measurement is of 4 coins (2 on each side). The last measurement (I assume) has to be 2 coins (1 on each side). This allows me to find the coin, and its weight in relation to the others sometimes. I can also, more often, find the coin and not know it's weight or find the weight but not know which of two coins it is. And sometimes, I get zilch. There is a strategy change I am missing, somewhere. Good puzzle - for ages last night I thought it was impossible, but now I am sure it is not!
     

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